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代碼:
#include <stdio.h>
#include <stdlib.h>
int ValidNum(char); //Check the word of Input.
int TransNum(char*); //Transfer the Numbers.
int main(void)
{
int No1=0, No2=0, No3, i, j, k;
char IOput[1024], Num1[512], Num2[512], op;
printf("Enter Your Operation: ");
gets(IOput);
/* Remove Space ' '. */
for(i=0; IOput[i]; ++i)
{
if(IOput[i] == ' ')
{
for(j=i; IOput[j]; ++j) IOput[j] = IOput[j+1];
IOput[j] = IOput[j+1];
--i;
}
}
/* Pick the 1st Number. */
for(i=0; ValidNum(IOput[i]); ++i) Num1[i] = IOput[i];
Num1[i] = '\0';
/* Pick Operation. */
op = IOput[i];
++i;
/* Pick the 2nd Number. */
for(j=0; ValidNum(IOput[i]); ++i, ++j) Num2[j] = IOput[i];
Num2[j] = '\0';
/* Transfer the Numbers. */
No1 = TransNum(Num1);
No2 = TransNum(Num2);
/* Do the Operation. */
switch(op)
{
case '+':
No3 = No1 + No2;
break;
case '-':
No3 = No1 - No2;
break;
case '*':
No3 = No1 * No2;
break;
case '/':
No3 = No1 / No2;
break;
default:
if(Num1[0] == '\0') printf("O(0)\n");
else printf("%s(%d)\n", Num1, No1);
system("PAUSE");
return 0;
}
/* Process Output String. */
if(No3 == 0)
{
IOput[0] = 'O';
IOput[1] = '\0';
}
else
{
i = 0;
k = No3;
if((j = k / 1000) > 0)
{
for(; j>0; --j, ++i) IOput[i] = 'M';
k %= 1000;
}
if((j = k / 500) > 0)
{
for(; j>0; --j, ++i) IOput[i] = 'D';
k %= 500;
}
if((j = k / 100) > 0)
{
for(; j>0; --j, ++i) IOput[i] = 'C';
k %= 100;
}
if((j = k / 50) > 0)
{
for(; j>0; --j, ++i) IOput[i] = 'L';
k %= 50;
}
if((j = k / 10) > 0)
{
for(; j>0; --j, ++i) IOput[i] = 'X';
k %= 10;
}
if((j = k / 5) > 0)
{
for(; j>0; --j, ++i) IOput[i] = 'V';
k %= 5;
}
for(; k>0; --k, ++i) IOput[i] = 'I';
IOput[i] = '\0';
}
printf("%s(%d) %c %s(%d) = %s(%d)\n", Num1, No1, op, Num2, No2, IOput, No3);
system("PAUSE");
return 0;
}
//------------------------------------------------------------------------------
int ValidNum(char word)
{
switch(word)
{
case 'O':
case 'I':
case 'V':
case 'X':
case 'L':
case 'C':
case 'D':
case 'M':
return 1;
}
return 0;
}
//------------------------------------------------------------------------------
int TransNum(char *Num)
{
int No=0, i;
for(i=0; Num[i]; ++i)
{
switch(Num[i])
{
case 'O':
No += 0;
break;
case 'I':
No += 1;
break;
case 'V':
No += 5;
break;
case 'X':
No += 10;
break;
case 'L':
No += 50;
break;
case 'C':
No += 100;
break;
case 'D':
No += 500;
break;
case 'M':
No += 1000;
break;
}
}
return No;
}
//------------------------------------------------------------------------------C++怎麼做....
複製內容到剪貼板
代碼:
#include <stdlib.h>
#include <iostream>
using namespace std;
//---------------------------------------------------------------------------
class Roma
{
private:
int Number;
string Str;
public:
Roma(int Input=0) : Number(Input) { Str = NumToStr(Input); }
Roma(char *Input) : Str(Input) { Number = StrToNum(Str); }
Roma(string Input) : Str(Input) { Number = StrToNum(Str); }
Roma(const Roma &Input) : Number(Input.Number), Str(Input.Str) {}
virtual ~Roma() {}
Roma operator +(const Roma &Operand) { return Roma(Number + Operand.Number); }
Roma operator -(const Roma &Operand) { return Roma(Number - Operand.Number); }
Roma operator *(const Roma &Operand) { return Roma(Number * Operand.Number); }
Roma operator /(const Roma &Operand) { return Roma(Number / Operand.Number); }
Roma& operator =(const Roma &Operand);
int StrToNum(void) { return Number; }
int StrToNum(string&);
string NumToStr(void) { return Str; }
string NumToStr(int);
friend istream& operator >>(istream &in_data, Roma &roma);
friend ostream& operator <<(ostream &out_data, const Roma &roma)
{ return out_data << roma.Str << '(' << roma.Number << ')'; }
};
//---------------------------------------------------------------------------
int main(void)
{
char op, buffer[1024];
int pos, i, j;
string Input;
Roma Num1, Num2;
cout << "Enter Your Operation:" << ends;
cin >> ws;
cin.getline(buffer, 1024);
/* Remove Space ' '. */
for(i=0; buffer[i]; ++i)
{
if(buffer[i] == ' ')
{
for(j=i; buffer[j]; ++j) buffer[j] = buffer[j+1];
buffer[j] = buffer[j+1];
--i;
}
}
Input = buffer;
/* Devide 2 Numbers. */
pos = Input.find_first_of("+-*/", 0);
if(pos == -1)
{
Num1 = Input;
cout << Num1 << endl;
system("PAUSE");
return 0;
}
/* Pick the Operation. */
op = Input.at(pos);
/* Pick the 2 Numbers. */
Num1 = Input.substr(0, pos);
Num2 = Input.substr(pos+1);
/* Do the Operation. */
switch(op)
{
case '+':
cout<<Num1<<' '<<op<<' '<<Num2<<" = "<<Num1+Num2<<endl;
break;
case '-':
cout<<Num1<<' '<<op<<' '<<Num2<<" = "<<Num1-Num2<<endl;
break;
case '*':
cout<<Num1<<' '<<op<<' '<<Num2<<" = "<<Num1*Num2<<endl;
break;
case '/':
cout<<Num1<<' '<<op<<' '<<Num2<<" = "<<Num1/Num2<<endl;
break;
}
system("PAUSE");
return 0;
}
//---------------------------------------------------------------------------
Roma& Roma::operator =(const Roma &Operand)
{
Number = Operand.Number;
Str = Operand.Str;
return *this;
}
//---------------------------------------------------------------------------
int Roma::StrToNum(string &str)
{
int No=0, i;
for(i=0; (unsigned)i<str.length(); ++i)
{
switch(str[i])
{
case 'O':
No += 0;
break;
case 'I':
No += 1;
break;
case 'V':
No += 5;
break;
case 'X':
No += 10;
break;
case 'L':
No += 50;
break;
case 'C':
No += 100;
break;
case 'D':
No += 500;
break;
case 'M':
No += 1000;
break;
default:
str = str.substr(0, i);
}
}
if(str == "") str = "O";
return No;
}
//---------------------------------------------------------------------------
string Roma::NumToStr(int No)
{
if(No == 0) return string("O");
else
{
int i=0, j, k=No;
string str = "";
if((j = k / 1000) > 0)
{
for(; j>0; --j, ++i) str += 'M';
k %= 1000;
}
if((j = k / 500) > 0)
{
for(; j>0; --j, ++i) str += 'D';
k %= 500;
}
if((j = k / 100) > 0)
{
for(; j>0; --j, ++i) str += 'C';
k %= 100;
}
if((j = k / 50) > 0)
{
for(; j>0; --j, ++i) str += 'L';
k %= 50;
}
if((j = k / 10) > 0)
{
for(; j>0; --j, ++i) str += 'X';
k %= 10;
}
if((j = k / 5) > 0)
{
for(; j>0; --j, ++i) str += 'V';
k %= 5;
}
for(; k>0; --k, ++i) str += 'I';
return str;
}
}
//---------------------------------------------------------------------------
istream& operator >>(istream &in_data, Roma &roma)
{
string temp;
in_data >> temp;
roma = temp;
return in_data;
}
//---------------------------------------------------------------------------下面是羅馬數字轉int，沒有作規則檢查，不過要加也不難
輸入正確的羅馬數字，可以得到正確的數值
至於阿拉伯轉羅馬，查表比較快(大部分的情況下如果能靠查表解決，就不要硬算)
複製內容到剪貼板
代碼:
#include <cstdlib>
#include <iostream>
#include <cstring>
using namespace std;
int GetDigitValue(char d)
{
switch (d)
{
case 'M': return 1000;
case 'D': return 500;
case 'C': return 100;
case 'L': return 50;
case 'X': return 10;
case 'V': return 5;
case 'I': return 1;
//default: we can throw exception here...
}
return 0;
}
int GetRightNum(int* num, int length)
{
if (length == 1) return *num;
else if (length == 0) return 0;
else if (num[1] > num[0])
//it's easy to do rule check and throw exception here...
//but it's too late now and i'm going to bed -.-
return num[1]- num[0] + GetRightNum(num + 2, length - 2);
else return num[0] + GetRightNum(num + 1, length - 1);
}
int RomanToArabic(const char* roman)
{
int length = strlen(roman), re;
int* num = new int[length];
// try and catch here
for (int i = 0; i < length; i++)
num[i] = GetDigitValue(roman[i]);
re = GetRightNum(num, length);
delete[] num;
return re;
}
int main()
{
cout << RomanToArabic("XLIV") << endl;
cout << RomanToArabic("CMXLII") << endl;
cout << RomanToArabic("IL") << endl;
cout << RomanToArabic("MCM") << endl;
cout << RomanToArabic("MCMXCVI") << endl;
system("PAUSE");
}ArabicToRoman() 的部份若是採用string可以用替換的方式將4,9,40,90,400,900的字串替換掉,也是可以的
複製內容到剪貼板
代碼:
#include <iostream>
using namespace std;
char* ArabicToRoman(int ArabicNum,char* RomanString){
int nArray[8]={1000,500,100,50,10,5,1,0};
char chArray[7]={'M','D','C','L','X','V','I'};
int nTemp=ArabicNum;
char* pStr=RomanString;
int nPtr=0;
if(nTemp==0)
*pStr++='O';
while(nTemp){
if(nTemp<nArray[nPtr])
++nPtr;
else{
nTemp-=nArray[nPtr];
*pStr++=chArray[nPtr];
}
}
*pStr='\0';
return RomanString;
}
int RomanToArabic(char* RomanString){
int nTemp;
if(*RomanString=='\0')
return 0;
switch (*RomanString){
case 'M':
nTemp=1000;
break;
case 'D':
nTemp=500;
break;
case 'C':
nTemp=100;
break;
case 'L':
nTemp=50;
break;
case 'X':
nTemp=10;
break;
case 'V':
nTemp=5;
break;
case 'I':
nTemp=1;
break;
case 'O':
nTemp=0;
break;
}
return nTemp+=RomanToArabic(RomanString+1);
}
int main(void){
char s[255];
cout<<ArabicToRoman(1996,s)<<endl;
cout<<RomanToArabic("MDCCCCLXXXXVI")<<endl;
system("PAUSE");
}下面這篇是數字轉羅馬數字
複製內容到剪貼板
代碼:
/*
分成百位,十位,個位來處理.
個位(1-9): I, II, III, IV, V, VI, VII, VIII, IX (0為空字串)
十位(1-9): X, XX, XXX, XL, L, LX, LXX, LXXX, XC (0為空字串)
百位(1-9): C, CC, CCC, CD, D, DC, DCC, DCCC, CM (0為空字串)
按各位數得到的字串組合在一起便是羅馬數字字串
*/
#include<stdio.h>
#include<stdlib.h>
#include<string.h>
char* sUnidigit[]={"","I","II","III","IV","V","VI","VII","VIII","IX"};
char* sTen[]={"","X","XX","XXX","XL","L","LX","LXX","LXXX","XC"};
char* sCentum[]={"","C","CC","CCC","CD","D","DC","DCC","DCCC","CM"};
char* arabia_roman(char* sDest,int nArabia){
sDest[0]='\0';
(nArabia>99)&&strcat(sDest,sCentum[nArabia/100])&&(nArabia%=100);
(nArabia>9)&&strcat(sDest,sTen[nArabia/10])&&(nArabia%=10);
(nArabia>0)&&strcat(sDest,sUnidigit[nArabia]);
return sDest;
}
int main(){
char str[256];
int i,j;
for(i=1;i<=100;i++){
if(i%5==0)
printf("%3d=%8s\n",i,arabia_roman(str,i));
else
printf("%3d=%8s",i,arabia_roman(str,i));
}
system("pause");
}[
本帖最後由 philxyz0316 於 2006-8-27 13:06 編輯 ]
